web.xml 中定義的 Servlet 必須通過相應的 servlet 映射才能訪問。
缺少有效的 servlet 映射會阻止用戶對未映射的 servlet 的所有訪問。
例 1：web.xml 中的以下條目定義了 ExampleServlet，但未定義相應的 servlet 映射。
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4">
<servlet>
<servlet-name>ExampleServlet</servlet-name>
<servlet-class>com.class.ExampleServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
</web-app>
[1] Standards Mapping - OWASP Top 10 2010 - (OWASP 2010) A6 Security Misconfiguration
[2] Standards Mapping - OWASP Top 10 2004 - (OWASP 2004) A9 Application Denial of Service
[3] Standards Mapping - Security Technical Implementation Guide Version 3 - (STIG 3) APP6080 CAT II
[4] Standards Mapping - Security Technical Implementation Guide Version 3.4 - (STIG 3.4) APP6080 CAT II
[5] Standards Mapping - Common Weakness Enumeration - (CWE) CWE ID 730
[6] Sun Microsystems, Inc. Java Servlet Specification 2.4
[7] Standards Mapping - Payment Card Industry Data Security Standard Version 1.1 - (PCI 1.1) Requirement 6.5.9